A) \[3{{Q}_{0}},\ 3{{V}_{0}},\ 3{{E}_{0}}\]
B) \[{{Q}_{0}},\ 3{{V}_{0}},\ 3{{E}_{0}}\]
C) \[{{Q}_{0}},\ \frac{{{V}_{0}}}{3},\ 3{{E}_{0}}\]
D) \[{{Q}_{0}},\ \frac{{{V}_{0}}}{3},\ \frac{{{E}_{0}}}{3}\]
Correct Answer: D
Solution :
When there is no battery, charge remains same while potential difference and electric field decreases i.e. \[Q'={{Q}_{0}},V'=\frac{{{V}_{0}}\times 3}{9}=\frac{{{V}_{0}}}{3}\]and \[E'=\frac{{{E}_{0}}\times 3}{9}=\frac{{{E}_{0}}}{3}\]You need to login to perform this action.
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