A) \[80\times {{10}^{-6}}\]
B) 800
C) 80
D) 8000
Correct Answer: B
Solution :
\[U=\frac{{{Q}^{2}}}{2C}=\frac{{{(40\times {{10}^{-6}})}^{2}}}{2\times {{10}^{-6}}\times 10}=\frac{16\times {{10}^{-10}}}{2\times {{10}^{-5}}}=8\times {{10}^{-5}}J\] \[=8\times {{10}^{-5}}\times {{10}^{7}}=800\,erg\]You need to login to perform this action.
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