A) The charge on the capacitor increases
B) The voltage across the plates decreases
C) The capacitance increases
D) The electrostatic energy stored in the capacitor increases
Correct Answer: D
Solution :
When the battery is disconnected, the charge will remain same in any case. Capacitance of a parallel plate capacitor is given by \[C=\frac{{{\varepsilon }_{0}}A}{d}\] When d is increased, capacitance will decreases and because the charge remains the same, so according to \[q=CV,\] the voltage will increase, Hence the electrostatics energy stored in the capacitor will increase.
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