A) \[11.2\mu F\]
B) \[15.6\mu F\]
C) \[19.2\mu F\]
D) \[22.4\mu F\]
Correct Answer: A
Solution :
\[C=\frac{{{\varepsilon }_{0}}KA}{d}\] Þ \[\frac{{{C}_{1}}}{{{C}_{2}}}=\frac{{{K}_{1}}}{{{K}_{2}}}\times \frac{{{d}_{2}}}{{{d}_{1}}}\] \[\frac{2}{{{C}_{2}}}=\frac{1}{2.8}\times \frac{(0.4/2)}{(0.4)}\] Þ \[{{C}_{2}}\,=\,11.2\,\mu \,F\]You need to login to perform this action.
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