A) \[4\pi {{\varepsilon }_{0}}\frac{ab}{b-a}\]
B) \[4\pi {{\varepsilon }_{0}}\,(a+b)\]
C) \[4\pi {{\varepsilon }_{0}}b\]
D) \[4\pi {{\varepsilon }_{0}}\frac{{{b}^{2}}}{b-a}\]
Correct Answer: D
Solution :
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