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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    The distance between the plates of a parallel plate capacitor is \[d\]. A metal plate of thickness \[d/2\] is placed between the plates. The capacitance would then be [MP PMT 1994]

    A)                    Unchanged                   

    B)            Halved

    C)                    Zero                                 

    D)            Doubled

    Correct Answer: D

    Solution :

               \[C=\frac{{{\varepsilon }_{0}}A}{d-(d/2)}=2\frac{{{\varepsilon }_{0}}A}{d}\]


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