JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    The capacitance of an air capacitor is \[15\mu F\]the separation between the parallel plates is\[6mm\]. A copper plate of \[3mm\] thickness is introduced symmetrically between the plates.  The capacitance now becomes                  [MP PMT 1995]

    A)                    \[5\mu F\]

    B)                                      \[7.5\mu F\]

    C)                    \[22.5\mu F\]               

    D)            \[30\mu F\]

    Correct Answer: D

    Solution :

                       By using \[{{C}_{air}}=\frac{{{\varepsilon }_{0}}A}{d},\] \[{{C}_{medium}}=\frac{{{\varepsilon }_{0}}A}{d-t+\frac{t}{K}}\] For K = ¥    \[{{C}_{medium}}=\frac{{{\varepsilon }_{0}}A}{d-t}\] Þ \[\frac{{{C}_{m}}}{{{C}_{a}}}=\frac{d}{d-t}\] Þ \[\frac{{{C}_{m}}}{15}=\frac{6}{6-3}\] Þ \[{{C}_{m}}=30\mu \,C\]


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