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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    A charge of \[{{10}^{-9}}C\] is placed on each of the 64 identical drops of radius \[2cm\]. They are then combined to form a bigger drop. Find its potential                                                                     [MP PET 1997]

    A)                    \[7.2\times {{10}^{3}}V\]

    B)            \[7.2\times {{10}^{2}}V\]

    C)                    \[1.44\times {{10}^{2}}V\]                                         

    D)            \[1.44\times {{10}^{3}}V\]

    Correct Answer: A

    Solution :

                       \[V={{n}^{2/3}}v\] Þ \[V={{(64)}^{2/3}}\times 9\times {{10}^{9}}\times \frac{{{10}^{-9}}}{(2\times {{10}^{-2}})}\] = 7.2 ´ 103 V


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