A) Increased proportional to 2
B) Decreased proportional to \[\frac{1}{2}\]
C) Increased proportional to \[\sqrt{2}\]
D) Decreased proportional to \[\frac{1}{\sqrt{2}}\]
Correct Answer: B
Solution :
\[{{E}_{medium}}=\frac{{{E}_{air}}}{K}=\frac{E}{2}\]You need to login to perform this action.
You will be redirected in
3 sec