A) \[144\times {{10}^{-9}}F\]
B) \[40pF\]
C) \[160pF\]
D) \[1.44\mu F\]
Correct Answer: C
Solution :
\[C=\frac{{{\varepsilon }_{0}}A}{d-t+\frac{t}{K}}=\frac{1}{4\pi \times 9\times {{10}^{9}}}.\frac{\pi \,{{(0.12)}^{2}}}{\left( 2+\frac{1}{2} \right)\,{{10}^{-3}}}\] \[=\frac{2\times 144\times {{10}^{-10}}}{36\times 5}=160pF\]You need to login to perform this action.
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