A) \[C{{V}^{2}}/4\]
B) \[C{{V}^{2}}/2\]
C) \[3C{{V}^{2}}/4\]
D) \[C{{V}^{2}}\]
Correct Answer: D
Solution :
Extra charge Q = (2CV ? CV) = CV flows through potential V of the battery. Thus W = QV = \[C{{V}^{2}}\]You need to login to perform this action.
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