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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
     125 identical drops each charged to the same potential of \[50\ volts\] are combined to form a single drop. The potential of the new drop will be                                                              [MP PET 1997]

    A)                    \[50\,V\]

    B)                                      \[250\ V\]

    C)                    \[500\ V\]                      

    D)            \[1250\ V\]

    Correct Answer: D

    Solution :

               \[V={{n}^{\text{2}/\text{3}}}v\Rightarrow V=\text{ }{{\left( \text{125} \right)}^{\text{2}/\text{3}}}\times \text{5}0\text{ }=\text{ 125}0V\]


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