A) \[25\times {{10}^{-2}}J\]
B) \[-12.5\times {{10}^{-2}}J\]
C) \[-25\times {{10}^{-2}}J\]
D) \[12.5\times {{10}^{-2}}J\]
Correct Answer: A
Solution :
\[{{W}_{ext}}=\frac{1}{2}C'V{{'}^{2}}-\frac{1}{2}C{{V}^{2}}\] \[=\left( \frac{1}{2} \right)\,\left( \frac{C}{2} \right)\,{{(2V)}^{2}}-\frac{1}{2}C{{V}^{2}}=\frac{1}{2}C{{V}^{2}}\] \[{{W}_{ext}}=\frac{1}{2}\times 50\times {{10}^{-6}}\times {{(100)}^{2}}=25\times {{10}^{-2}}J\]
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