A) \[1.694\times {{10}^{9}}{{m}^{2}}\]
B) \[4.529\times {{10}^{9}}{{m}^{2}}\]
C) \[9.281\times {{10}^{9}}\ {{m}^{2}}\]
D) \[12.981\times {{10}^{9}}\ {{m}^{2}}\]
Correct Answer: A
Solution :
We have \[C=\frac{{{\varepsilon }_{0}}A}{d}\] Þ \[A=\frac{Cd}{{{\varepsilon }_{0}}}=\frac{3\times 5\times {{10}^{-3}}}{8.85\times {{10}^{-12}}}\] \[=1.7\times {{10}^{9}}{{m}^{2}}\]
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