A) 0.1 mm
B) 0.5 mm
C) 1.0 mm
D) 2.0 mm
Correct Answer: C
Solution :
\[T=\frac{rh\rho g}{2}\Rightarrow 75\times {{10}^{-3}}=\frac{3\times {{10}^{-2}}\times r\times {{10}^{3}}\times 9.8}{2}\] \[\Rightarrow r=\frac{1}{2}mm\]\[\therefore D=2r=1\ mm\]
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