A) \[5\times {{10}^{-3}}N/m\]
B) \[5\times {{10}^{-2}}N/m\]
C) \[5\,N/m\]
D) \[50\,N/m\]
Correct Answer: B
Solution :
\[T=\frac{F}{2\pi r}=\frac{6.28\times {{10}^{-4}}}{2\times 3.14\times 2\times {{10}^{-3}}}=5\times {{10}^{-2}}N/m\]
You need to login to perform this action.
You will be redirected in
3 sec
