A) 0.1 mm
B) 0.5 mm
C) 1 mm
D) 2 mm
Correct Answer: C
Solution :
\[h=\frac{2T}{rdg}\] Þ \[r=\frac{2T}{hdg}=\frac{2\times 75\times {{10}^{-3}}}{15\times {{10}^{-3}}\times {{10}^{3}}\times 10}=1\,mm\]
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