A) M
B) 2M
C) M/2
D) 4M
Correct Answer: B
Solution :
Mass of liquid in capillary tube \[M=\pi {{R}^{2}}H\times \rho \]\ \[M\propto {{R}^{2}}\times \left( \frac{1}{R} \right)\] (As H µ 1/R) \ \[\Mu \propto R\]. If radius becomes double then mass will becomes twice.
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