A) 4h
B) 3h
C) 2h
D) H
Correct Answer: C
Solution :
\[h\propto \frac{1}{r}\]Þ \[\frac{{{h}_{2}}}{{{h}_{1}}}=\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{{{D}_{1}}}{{{D}_{2}}}=2\]Þ \[{{h}_{2}}=2{{h}_{1}}\]
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