A) \[\frac{T\cos \theta }{xd}\]
B) \[\frac{2T\cos \theta }{xdg}\]
C) \[\frac{2T}{xdg\cos \theta }\]
D) \[\frac{T\cos \theta }{xdg}\]
Correct Answer: B
Solution :
Let the width of each plate is b and due to surface tension liquid will rise upto height h then upward force due to surface tension = \[2Tb\cos \theta \] ?(i) Weight of the liquid rises in between the plates = \[Vdg=(bxh)dg\] ?(ii) Equating (i) and (ii) we get ,\[2T\cos \theta =bxhdg\] \[\therefore h=\frac{2T\cos \theta }{xdg}\]You need to login to perform this action.
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