A) 1, 5, ethyl methanoate
B) 0.1, 0.05, methyl ethanoate
C) 0.1, 0.05, ethyl ethanoate
D) 1, 5, methyl methanoate.
Correct Answer: B
Solution :
6 g of ethanoic acid \[=\frac{6}{60}mol\] \[=\frac{1}{10}=0.1\,mol\] 1.6 g of methanol =\[\frac{1.6}{32}mol=0.05\,mol\] \[C{{H}_{3}}COOH+C{{H}_{3}}OH\xrightarrow{{}}\underset{Methyl\,ethanoate}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O{{C}_{3}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
