A)
Molecular formula
Boiling point \[\left( {}^\circ C \right)\]
\[{{C}_{3}}{{H}_{4}}\]
-85
B)
Molecular formula
Boiling point \[\left( {}^\circ C \right)\]
\[{{C}_{2}}{{H}_{6}}\]
-185
C)
Molecular formula
Boiling point \[\left( {}^\circ C \right)\]
\[{{C}_{3}}{{H}_{6}}\]
-69
D)
Molecular formula
Boiling point \[\left( {}^\circ C \right)\]
\[{{C}_{3}}{{H}_{8}}\]
-42
Correct Answer: D
Solution :
Third member of alkane series is propane i.e., \[{{C}_{3}}{{H}_{8}}.\] Also, on moving down the series, boiling point goes on increasing hence, its boiling point should be higher than that of methane.
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