A) \[{{\left( C{{H}_{3}} \right)}_{3}}CONa+C{{H}_{3}}I\to \]
B) \[{{\left( C{{H}_{3}} \right)}_{3}}C=C{{H}_{2}}+C{{H}_{3}}OH\xrightarrow{{{H}_{2}}S{{O}_{4}}}\]
C) \[{{\left( C{{H}_{3}} \right)}_{3}}CBr+C{{H}_{3}}ONa\to \]
D) all give 100% yield
Correct Answer: A
Solution :
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