A) ethyl iodide
B) methyl iodide
C) propyl lodide
D) mixture of [a] and [b]
Correct Answer: A
Solution :
The alcohol Z in that case should be \[{{C}_{2}}{{H}_{5}}OH\]and the compound Y should be ethyl iodide. X is therefore diethyl ether \[\left( {{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}} \right)\]
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