| Directions : (11-15) |
| AC Voltage Applied to an Inductor |
| Let a source of alternating e.m.f. \[E={{E}_{0}}\,\sin \omega t\]be connected to a circuit containing a pure inductance L. If I is the value of instantaneous current in the ciruit, then \[I={{I}_{0}}\sin \left( \omega t-\frac{\pi }{2} \right)\]. The inductive reactance limits the current in a purely inductive circuit and is given by \[{{X}_{L}}=\omega L\]. |
 |
A) \[15\,\Omega \]
B) \[7\centerdot 5\Omega \]
C) \[8\centerdot 8\Omega \]
D) \[10\,\Omega \]
Correct Answer: C
Solution :
Inductive reactance, \[{{X}_{L}}=\omega L=2\pi vL=2\pi \times 100\times 14\times {{10}^{-3}}\] \[{{X}_{L}}=8\,.\,8\Omega \]
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