A) \[0\centerdot 337A\]
B) \[0\centerdot 721A\]
C) \[1\centerdot 521A\]
D) \[2\centerdot 522A\]
Correct Answer: A
Solution :
Inductive reactance, \[{{X}_{L}}=\omega L=2\pi vL=2\times 3\,.\,14\times 50\times 2=628\,\Omega \] \[{{I}_{0}}=\frac{{{E}_{0}}}{{{X}_{L}}}\Rightarrow {{I}_{0}}=\frac{\sqrt{2}\times {{E}_{v}}}{{{X}_{L}}}=\frac{\sqrt{2}\times 150}{628}=0\,.\,337\,A\]
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