A) 550 kW
B) 650 kW
C) 600 kW
D) 700 kW
Correct Answer: C
Solution :
Line power loss \[={{I}^{2}}R\] RMS current in the coil, \[I=\frac{P}{{{V}_{1}}}=\frac{800\times {{10}^{3}}}{4000}=200\,A\] \[\therefore \]Power loss \[={{\left( 200 \right)}^{2}}\times 15=600\,kW\]You need to login to perform this action.
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