A) \[20\Omega \]
B) \[40\Omega \]
C) \[60\Omega \]
D) \[50\Omega \]
Correct Answer: A
Solution :
\[{{X}_{L}}=\omega L=2\pi vL=2\times 3.14\times 159\,.\,24\times 20\times {{10}^{-3}}\] \[\Rightarrow {{X}_{L}}=20\,W\]
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