12th Class Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Case Based (MCQs) - Alternating Currents

  • question_answer
    The maximum value of current when inductance of 2 H is connected to 150V, 50 Hz supply is:

    A) 0.337 A                        

    B) 0.721 A 

    C) 1.521 A                        

    D) 2.522 A

    Correct Answer: A

    Solution :

    (a) 0.337 A Inductive reactance, \[{{X}_{L}}=\omega L=2\pi vL\] \[=2\times 3.14\times 50\times 2=628\,\Omega \] \[{{l}_{0}}=\frac{{{E}_{0}}}{{{X}_{L}}}\Rightarrow {{l}_{0}}=\frac{\sqrt{2}\times {{E}_{V}}}{{{X}_{L}}}=\frac{\sqrt{2}\times {{E}_{V}}}{{{X}_{L}}}\] \[=\frac{\sqrt{2}\times 150}{628}=0.337\,A\]


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