12th Class Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Case Based (MCQs) - Alternating Currents

  • question_answer
    Direction: Q.26 to Q.30
    When the frequency of AC supply is such that the inductive reactance and capacitive reactance become equal, the impedance of the series LCR circuit is equal to the ohmic resistance in the circuit. Such a series LCR circuit is known as resonant series LCR circuit and the frequency of the AC supply is known as resonant frequency.
    Resonance phenomenon is exhibited by a circuit only if both L and C are present in the circuit. We cannot have resonance in a RL or RC circuit.
    A series LCR circuit with \[L=0.12\text{ }H,\text{ }C=480\text{ }nF,\text{ }R=23\,\Omega \]is connected to a 230 V variable frequency supply.
    Based on the above information, answer the following questions.
    Find the value of source frequency for which current amplitude is maximum.

    A) 222.32 Hz                     

    B) 550.52 Hz

    C) 663.48 Hz                     

    D) 770 Hz

    Correct Answer: C

    Solution :

    (c) 663.48 Hz Here,    \[L=0.12\,H,C=480\,nF=480\times {{10}^{-9}}F\]             \[R=23\,\Omega ,\,V=230\,V\]             \[{{V}_{0}}=\sqrt{2}\times 230=325.22\,V\]             \[{{l}_{0}}=\frac{{{V}_{0}}}{\sqrt{{{R}^{2}}+{{\left( \omega L-\frac{1}{\omega C} \right)}^{2}}}}\] At resonance, \[\omega L-\frac{1}{\omega C}=0\] \[\omega =\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.12\times 480\times {{10}^{9}}}}=4166.67\,\,rad\,{{s}^{-1}}\]\[{{v}_{R}}=\frac{4166.67}{2\times 3.14}=663.48\,Hz\]


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