A) current through its secondary is about four times that of the current through its primary
B) voltage across its secondary is about four times that of the voltage across its primary
C) voltage across its secondary is about two times that of the voltage across its primary
D) voltage across its secondary is about \[\frac{1}{2\sqrt{2}}\] times that of the voltage across its primary
Correct Answer: A
Solution :
(a) current through its secondary is about four times that of the current through its primary In a transformer, the primary and secondary currents are related by \[{{l}_{S}}=\left( \frac{{{N}_{P}}}{{{N}_{S}}} \right){{l}_{P}}\] and the voltages are related by \[{{V}_{S}}=\left( \frac{{{N}_{P}}}{{{N}_{S}}} \right){{V}_{P}}\] where, subscripts p and s refer to the primary and secondary of the transformer. Here, \[{{V}_{P}}=V,\frac{{{N}_{P}}}{{{N}_{S}}}=4\] \[\therefore {{l}_{S}}=4{{l}_{P}}\] And \[{{V}_{S}}=\left( \frac{1}{4} \right)V=\frac{V}{4}\]
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