A) 0.125 A
B) 2.52 A
C) 1.51 A
D) 3.52 A
Correct Answer: A
Solution :
(a) 0.125 A As \[\frac{{{l}_{P}}}{{{l}_{S}}}=\frac{{{E}_{S}}}{{{E}_{P}}}\Rightarrow {{l}_{P}}=\frac{{{E}_{S}}}{{{E}_{P}}}\times {{l}_{S}}=\frac{3}{120}\times 5=0.125\,A\]
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