A) 0.337 A
B) 0.721 A
C) 1.521 A
D) 2.522 A
Correct Answer: A
Solution :
(a) 0.337 A Inductive reactance, \[{{X}_{L}}=\omega L=2\pi vL\] \[=2\times 3.14\times 50\times 2=628\,\Omega \] \[{{l}_{0}}=\frac{{{E}_{0}}}{{{X}_{L}}}\Rightarrow {{l}_{0}}=\frac{\sqrt{2}\times {{E}_{V}}}{{{X}_{L}}}=\frac{\sqrt{2}\times {{E}_{V}}}{{{X}_{L}}}\] \[=\frac{\sqrt{2}\times 150}{628}=0.337\,A\]You need to login to perform this action.
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