| Direction: Q.6 to Q.10 |
| Let a source of alternating e.m.f. \[E={{E}_{0}}\sin \,\,\omega t\] be connected to a circuit containing a pure inductance L. If l is the value of instantaneous current in the circuit, then \[l={{l}_{0}}\sin \left( \omega t-\frac{\pi }{2} \right)\]. The inductive reactance limits the current in a purely inductive circuit and is given by \[{{X}_{L}}=\omega L\]. |
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| Read the above passage carefully and give the answer of the following questions: |
A) \[15\,\Omega \]
B) \[7.5\,\Omega \]
C) \[8.8\,\Omega \]
D) \[10\,\Omega \]
Correct Answer: C
Solution :
(c) \[8.8\,\Omega \] Inductive reactance. \[{{X}_{L}}=\omega L=2\pi vL=2\pi \times 100\times 14\times {{10}^{-3}}\] \[{{X}_{L}}=8.8\,\Omega \]
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