A) \[7010{{m}^{2}}\]
B) \[7392{{m}^{2}}\]
C) \[8000{{m}^{2}}\]
D) \[9002{{m}^{2}}\]
Correct Answer: B
Solution :
Area of the race track = Area of the outer circle Area of the inner circle \[=\pi {{R}^{2}}-\pi {{r}^{2}}\] \[=\frac{22}{7}\left( {{56}^{2}}-{{28}^{2}} \right)\] \[=\frac{22}{7}\times 84\times 28=7392\,{{m}^{2}}\]
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