A) \[190\,c{{m}^{2}}\]
B) \[198.14\,c{{m}^{2}}\]
C) \[201.14\,c{{m}^{2}}\]
D) \[222.14\,c{{m}^{2}}\]
Correct Answer: C
Solution :
| In the figure, we have 4-quadrants of radius \[8cm\] |
| \[\therefore \] Area of all quadrants \[=4\times \frac{1}{4}\pi {{r}^{2}}=\pi {{r}^{2}}\] |
| \[=\frac{22}{7}\times 8\times 8=201.14c{{m}^{2}}\] |
| So, option [c] is correct. |
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