A) \[42.57c{{m}^{2}}\]
B) \[47.14c{{m}^{2}}\]
C) \[42c{{m}^{2}}\]
D) \[26.57c{{m}^{2}}\]
Correct Answer: B
Solution :
Total angle \[=80{}^\circ +40{}^\circ +30{}^\circ =150{}^\circ \] \[\therefore \] Area of the region \[=\frac{150{}^\circ }{360{}^\circ }\times \frac{22}{7}\times 6\times 6\] \[=\frac{118,800}{2520}=47.14\,\,c{{m}^{2}}\]
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