A) \[(\pi +12)\] inch
B) \[(\pi +10)\] inch
C) \[(2\pi +10)\]inch
D) \[(2\pi +12)\] inch
Correct Answer: D
Solution :
Perimeter of a sector \[=l+2r,\] where l is the length of the arc given by \[\frac{\theta }{360}\times 2\pi r\] |
Here, \[\theta =60{}^\circ \] and \[r=6\] inch |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,l=\frac{\theta }{360}\times 2\times \pi \times 6\] |
and \[2r=2\times 6=12\] |
\[\therefore \] Perimeter \[=(2\pi +12)\] inch |
So, option [d] is correct. |
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