A) \[12.57\,c{{m}^{2}}\]
B) \[14.8\,c{{m}^{2}}\]
C) \[20\,c{{m}^{2}}\]
D) \[26.57\,c{{m}^{2}}\]
Correct Answer: A
Solution :
| [a] Required area |
| \[=\frac{22}{7}\times 3\times 3\times \frac{160{}^\circ }{360{}^\circ }=\frac{88}{7}=12.57c{{m}^{2}}\] |
| So, option [a] is correct. |
You need to login to perform this action.
You will be redirected in
3 sec
