A) 21 sq. units
B) 35 sq. units
C) 42 sq, units
D) 45 sq, units
Correct Answer: A
Solution :
The coordinates of the vertices P, Q and \[R(6,9)\], \[(2,3)\]and \[(9,3)\] respectively. |
Now, base of the |
\[\Delta PQR=QR=\sqrt{{{(9-2)}^{2}}+{{(3-3)}^{2}}}\] |
\[=\sqrt{49+0}=7\] units |
and height of the \[\Delta PQR\]=Perpendicular distance from the vertex P to the base \[QR=(9-3)=6\] units. |
\[\therefore \] Area of |
\[\Delta PQR=\frac{1}{2}\times \text{base}\times \text{height =}\frac{1}{2}\times 7\times 6=21\,sq.\]. units |
So, option [a] is Correct. |
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