A) \[\sqrt{10}\]and \[\sqrt{8}\]respectively
B) \[2\] and \[\sqrt{52}\] respectively
C) \[\sqrt{2}\] and \[\sqrt{10}\] respectively
D) None of these
Correct Answer: B
Solution :
Diagonal \[PR=\sqrt{{{(4-4)}^{2}}+{{(5-3)}^{2}}}\] |
\[=\sqrt{{{0}^{2}}+{{(2)}^{2}}}=\sqrt{4}=2\] |
and Diagonal \[QS=\sqrt{{{(7-1)}^{2}}+{{(6-2)}^{2}}}\] |
\[=\sqrt{{{(6)}^{2}}+{{(4)}^{2}}}=\sqrt{36+16}=\sqrt{52}\] |
So, option [b] is correct. |
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