10th Class Mathematics Coordinate Geometry Question Bank Case Based (MCQs) - Coordinate Geometry

The height of the quadrilateral PQRS taking SR as the base is:

A) \[\frac{\sqrt{10}}{5}\]units

B) \[\frac{2\sqrt{10}}{5}\]units

C) \[3\sqrt{10}\]units

D) \[\frac{3\sqrt{10}}{5}\]units

Correct Answer: C

Solution :

Area of parallelogram \[\text{PQR5}=\text{base}\times \text{height}\]

\[6=SR\times \text{height}\]

\[\therefore \text{ }\,\,Height=\frac{6}{SR}=\frac{6}{\sqrt{10}}=\frac{3\sqrt{10}}{5}\]

So, option [d] is correct.