A) \[4\text{ }A/{{m}^{2}}\]
B) \[1\text{ }A/{{m}^{2}}\]
C) \[2A/{{m}^{2}}\]
D) \[8\text{ }A/{{m}^{2}}\]
Correct Answer: A
Solution :
(a) \[4\text{ }A/{{m}^{2}}\] Given \[l=40\,\,A;A=10\,{{m}^{2}}\] \[\therefore \] Current density, \[J=\frac{l}{A}\] or \[J=\frac{40}{10}=4A/{{m}^{2}}\]
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