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  5. Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर

12th Class Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Case Based (MCQs) - Current Electricity

  • question_answer
    4 cells each of emf 2V and internal resistance of \[1\Omega \] are connected in parallel to a load resistor of \[2\Omega \]. Then the current through the load resistor is :

    A) 2A

    B) 1.5 A

    C) 1A

    D) 0.888 A

    Correct Answer: D

    Solution :

    \[I=\frac{mE}{mR+r}\], m = number of cells = 4 \[E=2V,\,\,\,R=2\Omega ,\,\,r=1\Omega \] \[I=\frac{8}{8+1}=\frac{8}{9}=0.888A\]


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