12th Class Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Case Based (MCQs) - Current Electricity

  • question_answer
    4 cells each of emf 2 V and internal resistance of \[1\,\Omega \]are connected in parallel to a load resistor of \[2\,\Omega \]. Then the current through the load resistor is

    A) 2 A                              

    B) 1.5 A    

    C) 1 A                              

    D) 0.888 A       

    Correct Answer: D

    Solution :

    (d) 0.888 A                                                                   \[l=\frac{m\varepsilon }{mR+r'}m=\text{number}\,\,\text{of}\,\,\text{cells}=4\]                         \[\varepsilon =2\,V,\,R=2\,\Omega ,\,r=1\,\Omega \]                         \[l=\frac{8}{8+1}=\frac{8}{9}=0.888\,A\]


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