question_answer

Direction: Q.41 to Q.45

In 1942, a German physicist Kirchhoff’s extended Ohm's law to complicated circuits and gave two laws, which enable us to determine current in any part of such a circuit. According to Kirchhoff’s first rule, the algebraic sum of the currents meeting at a junction in a closed electric circuit is zero. The current flowing in a conductor towards the junction is taken as positive and the current flowing away from the junction is taken as negative. According to Kirchhoff’s second rule, in a closed loop, the algebraic sum of the emf’s and algebraic sum of the products of current and resistance in the various emf of the loop is zero. While traversing a loop, if negative pole of the cell is encountered first, then its emf is negative, otherwise positive.

Read the above passage carefully and give the answer of the following questions:

The value of current / in the given circuit is:

A) 4.5 A                           

B) 3.7 A    

C) 2.0 A                           

D) 2.5 A