A) 4 V
B) 5.6 V
C) 2.8 V
D) 6 V
Correct Answer: B
Solution :
(b) 5.6 V Apply KVL in the given circuit, \[6-8l-4-2l=0\] Or \[2-10l=0\] Or \[l=\frac{2}{10}=0.2\,A\] \[{{V}_{AB}}=4+l\times 8=4+0.2\times 8=5.6\,V\]
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