A) \[1:2\]
B) \[2:1\]
C) \[1:3\]
D) \[3:1\]
Correct Answer: D
Solution :
(d) \[3:1\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}+{{l}_{2}}}{{{l}_{1}}-{{l}_{2}}}=\frac{8+4}{8-4}=\frac{12}{4}=\frac{3}{1}\]You need to login to perform this action.
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