A) 2
B) \[\frac{-1}{2\sqrt{1-{{x}^{2}}}}\]
C) \[\frac{2}{x}\]
D) \[1-{{x}^{2}}\]
Correct Answer: A
Solution :
Let \[y={{\cos }^{-1}}\left( 2{{x}^{2}}-1 \right)=2{{\cos }^{-1}}x\] Differentiating w.r.t \[{{\cos }^{-1}}\,x\], we get \[\frac{dy}{d\left( {{\cos }^{-1}}x \right)}=\frac{2d\left( {{\cos }^{-1}}x \right)}{d\left( {{\cos }^{-1}} \right)}=2\]You need to login to perform this action.
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