A) \[\left[ M{{L}^{2}}\,{{T}^{-2}}\,{{A}^{-1}} \right]\]
B) \[\left[ M{{L}^{3}}\,{{T}^{-3}}\,{{A}^{-1}} \right]\]
C) \[\left[ {{M}^{-1}}\,{{L}^{3}}\,{{T}^{-3}}\,A \right]\]
D) \[\left[ M{{L}^{-3}}\,{{T}^{-3}}\,{{A}^{-1}} \right]\]
Correct Answer: B
Solution :
Surface integral \[\oint{\overrightarrow{E}}\,.\,d\,\overrightarrow{S}\]is the net electric flux ove a closed surface S. \[\therefore \,\,\,\,\,\,\,\,\,\,\left[ {{\phi }_{E}} \right]=\left[ M{{L}^{3}}{{T}^{-3}}{{A}^{-1}} \right]\].
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